[ \mathcalF = N I = 200 \times 1.5 = 300 \ \textA-turns ] Flux: [ \Phi = \frac\mathcalF\mathcalR = \frac3007.96 \times 10^5 \approx 3.77 \times 10^-4 \ \textWb ]
So: [ ℛ = \frac0.3(4π × 10^-7)(400)(5 × 10^-4) ] [ ℛ = \frac0.34π × 10^-7 × 400 × 5 × 10^-4 ] First, 400 × 5 × 10⁻⁴ = 0.2 . Then 4π × 10⁻⁷ × 0.2 = 2.513 × 10⁻⁷ (approx). circuitos magneticos ejercicios resueltos