Cs50 Tideman - Solution

if (locked[start][i] && is_path(i, end)) return true;

After locking, the winner is the candidate with no incoming edges (nobody has locked[j][i] == true for that i ). Cs50 Tideman Solution

For a single voter’s ranks array, we need to update preferences[a][b] for every pair where a is preferred over b . if (locked[start][i] && is_path(i, end)) return true; After

break;

Stick with it. Get the small test cases working (3 candidates). Then scale up. And remember — in CS50, the Tideman problem is marked as “more comfortable” for a reason. If you complete it, you have truly leveled up. Get the small test cases working (3 candidates)

if (start == current) return true; for (int i = 0; i < candidate_count; i++) if (locked[current][i] && creates_cycle(start, i)) return true; return false;

(or Ranked Pairs) algorithm is widely considered the most difficult problem in CS50x.